Class 10 Carbon and Its Compounds
2024 Question Paper – Full Solutions

The actual CBSE Class 10 Science 2024 board exam theory questions from Chapter 4 – Carbon and Its Compounds (3 marks & 5 marks). Attempt each question on paper, then click to reveal the board-exam style model answer.

📄 2024 Board Paper ✍️ 3 & 5 Mark Questions 🧪 Chapter 4 Only 📝 NCERT-Based Model Answers
📋 21 questions — attempt each on paper first, then click "Show Answer" to self-check.

Section A

Based on Ethanol, Esterification & Dehydration Reaction

A1 3 Marks

Write the name and structural formula of an organic compound X having two carbon atoms in its molecule, whose name has the suffix "-ol".

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Model Answer

The compound X is Ethanol (C₂H₅OH), with structural formula CH₃–CH₂–OH. The suffix "-ol" indicates the presence of the hydroxyl (–OH) functional group, which is characteristic of alcohols. With exactly two carbon atoms, the compound is named ethanol.

NCERT Class 10 Science, Chapter 4, Page 78. Compound identification ("Compound X") questions are standard CBSE PYQ format.
A2 5 Marks

What happens when X (ethanol) is heated with excess concentrated sulphuric acid at 443 K? Write the chemical equation for the reaction, stating the conditions. Also state the role played by concentrated sulphuric acid in the reaction.

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Model Answer

When ethanol is heated with excess concentrated sulphuric acid at 443 K, it undergoes dehydration to form ethene (an unsaturated hydrocarbon).

CH₃–CH₂–OH --(Conc. H₂SO₄, 443 K)--> CH₂=CH₂ + H₂O

Conditions: Excess concentrated H₂SO₄, temperature of 443 K.

Role of concentrated H₂SO₄: It acts as a dehydrating agent — it removes a water molecule from ethanol.

NCERT Ch. 4, Page 85. This is one of the most frequently repeated board questions (appears almost every year).
A3 3 Marks

Name the hydrocarbon produced in the above reaction (Q.A2) and draw its electron dot structure.

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Model Answer

The hydrocarbon produced is Ethene (C₂H₄).

Electron dot structure: Each carbon atom has 4 valence electrons. In ethene, the two carbon atoms share two pairs of electrons between them (forming a double bond, C=C), and each carbon additionally forms a single covalent bond with two hydrogen atoms.

H H \ / C==C / \ H H (Each line = one shared electron pair; C=C double bond = 2 shared pairs; each C-H bond = 1 shared pair, 4 such bonds in total)

Total: 1 C=C double bond (2 shared electron pairs) + 4 C–H single bonds (4 shared electron pairs).

NCERT Ch. 4, Page 71–72.

Section B

Based on Homologous Series & Functional Groups

B1 3 Marks

Define a homologous series of carbon compounds.

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Model Answer

A homologous series is a series of organic compounds having the same functional group, the same general formula, and similar chemical properties, in which each successive member differs from the previous one by a –CH₂– unit (a difference of 14 u in molecular mass).

Example: Alkanes — CH₄, C₂H₆, C₃H₈, C₄H₁₀ ... (general formula CₙH₂ₙ₊₂)

NCERT Ch. 4, Page 76. This is a definitional question asked almost every year.
B2 3 Marks

Why is the melting and boiling point of C₄H₈ higher than that of C₃H₆ or C₂H₄?

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Model Answer

C₄H₈, C₃H₆, and C₂H₄ belong to the same homologous series (alkenes). As we move up a homologous series, the molecular mass increases. A higher molecular mass means a larger molecule with a greater number of electrons, which increases the strength of the intermolecular (van der Waals) forces of attraction between molecules.

Since C₄H₈ has the highest molecular mass among the three, it has the strongest intermolecular forces, and therefore requires more energy (higher temperature) to melt or boil — giving it the highest melting and boiling point.

NCERT Ch. 4, Page 77. Gradation of physical properties in a homologous series.
B3 3 Marks

Why do we not see any gradation in the chemical properties of homologous series compounds?

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Model Answer

Chemical properties of an organic compound are mainly decided by its functional group. Since all members of a homologous series contain the same functional group, they show similar chemical properties — there is no gradual change (gradation) in chemical behaviour as we move up the series, unlike physical properties (melting point, boiling point) which do show a gradual increase with molecular mass.

NCERT Ch. 4, Page 77.
B4 3 Marks

Write the name and structure of an aldehyde and a ketone, both having the molecular formula C₃H₆O.

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Model Answer

Both compounds have the same molecular formula C₃H₆O but belong to different homologous series — this is an example of functional isomerism.

Aldehyde — Propanal:

CH₃–CH₂–CHO

Ketone — Propanone (Acetone):

CH₃–CO–CH₃

The aldehyde group (–CHO) is always at the end of the carbon chain, while the ketone group (>C=O) occurs within the chain.

NCERT Ch. 4, Page 78–79. Functional isomerism between aldehydes and ketones is a classic board question.

Section C

Based on Bonding, Homologous Series of Aldehydes & Cyclic Structures

C1 3 Marks

Give reason: Carbon can neither form a C⁴⁺ cation nor a C⁴⁻ anion, but forms covalent compounds instead.

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Model Answer

Carbon has 4 electrons in its outermost shell (valence shell) and needs 4 more to complete its octet.

  • If carbon were to lose 4 electrons to form C⁴⁺, it would require a very large amount of energy because removing electrons from a small atom against the pull of the nucleus is difficult.
  • If carbon were to gain 4 electrons to form C⁴⁻, the nucleus (with only 6 protons) would find it very difficult to hold on to 10 electrons, making the ion highly unstable.

Therefore, carbon achieves a stable noble gas configuration by sharing its valence electrons with other atoms, forming covalent bonds instead of ionic bonds.

NCERT Ch. 4, Page 70. This reasoning-based question appears very frequently in board exams.
C2 3 Marks

What is a homologous series of carbon compounds? Write the molecular formula of any two consecutive members of the homologous series of aldehydes.

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Model Answer

Homologous series definition: A series of carbon compounds having the same functional group and general formula, where successive members differ by a –CH₂– unit (14 u), is called a homologous series.

Two consecutive members of the aldehyde series (general formula CₙH₂ₙO, functional group –CHO):

Methanal: HCHO → Ethanal: CH₃CHO

The difference between them is exactly one –CH₂– unit (14 u in molecular mass).

NCERT Ch. 4, Page 76–78.
C3 3 Marks

Draw the structure of the molecule cyclohexane, C₆H₁₂.

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Model Answer

Cyclohexane (C₆H₁₂) is a saturated cyclic (ring) hydrocarbon formed due to carbon's property of catenation.

CH₂ / \ CH₂ CH₂ | | CH₂ CH₂ \ / CH₂ (Six CH₂ units joined in a closed ring — each carbon bonded to 2 H atoms and 2 neighbouring C atoms by single bonds)

Since it is a closed ring with only single bonds, all 6 carbon atoms together carry exactly 12 hydrogen atoms, matching the formula C₆H₁₂.

NCERT Ch. 4, Page 71. Cyclic structures demonstrate carbon's versatility (catenation in ring form).

Section D

Based on Ethanol — Reactions with Na, H₂SO₄, Ethanoic Acid & KMnO₄

D1 3 Marks

Name a commercially important carbon compound having the functional group –OH, and write its molecular formula.

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Model Answer

The functional group –OH (hydroxyl) belongs to the alcohol family. The most commercially important alcohol is Ethanol, molecular formula C₂H₅OH (or CH₃CH₂OH).

It is commonly known as "alcohol" and is used as a solvent, in the preparation of medicines, and as a fuel (mixed with petrol).

NCERT Ch. 4, Page 78.
D2 5 Marks

Write chemical equations to show the reaction of ethanol with: (a) sodium metal, (b) excess concentrated sulphuric acid, (c) ethanoic acid in the presence of an acid catalyst, (d) acidified potassium dichromate. Also write the name of the product formed in each case.

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Model Answer

(a) Reaction with sodium metal:

2CH₃CH₂OH + 2Na → 2CH₃CH₂O⁻Na⁺ + H₂↑ Product: Sodium ethoxide + Hydrogen gas

(b) Reaction with excess conc. H₂SO₄ at 443 K (dehydration):

CH₃CH₂OH --(Conc. H₂SO₄, 443K)--> CH₂=CH₂ + H₂O Product: Ethene (H₂SO₄ acts as a dehydrating agent)

(c) Reaction with ethanoic acid + acid catalyst (Esterification):

CH₃COOH + C₂H₅OH --(conc. H₂SO₄)--> CH₃COOC₂H₅ + H₂O Product: Ethyl ethanoate (an ester, sweet-smelling)

(d) Reaction with acidified potassium dichromate (Oxidation):

CH₃CH₂OH + [O] --(Acidified K₂Cr₂O₇)--> CH₃COOH + H₂O Product: Ethanoic acid (K₂Cr₂O₇ acts as oxidising agent)
NCERT Ch. 4, Pages 84–87. This combined 5-mark reaction question is one of the most repeated question types in CBSE board papers.

Section E – Case-Based / Source-Based Questions

Versatile Nature of Carbon, Functional Groups & Isomerism

E1 5 Marks

Passage: More than 3 million carbon compounds have been discovered so far. The diversity of these compounds arises from carbon's capacity for bonding with other carbon atoms as well as with atoms of other elements. Most carbon compounds are poor conductors of electricity and have low melting and boiling points.

E1(a) 1 Mark

Write the molecular formula of the first two members of the homologous series of haloalkanes having the functional group –Br.

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Model Answer

The functional group –Br belongs to the bromoalkane (haloalkane) series.

First member: CH₃Br (Bromomethane) Second member: C₂H₅Br (Bromoethane)

The difference between them is one –CH₂– unit, consistent with homologous series rules.

NCERT Ch. 4, Page 78 (Table of functional groups).
E1(b) 3 Marks

Given below are the formulas of some functional groups: –OH, >C=O, –CHO. Write the name of these functional groups.

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Model Answer
  • –OHHydroxyl group (functional group of alcohols)
  • >C=O (carbon attached to oxygen by a double bond, within the chain) → Ketone (Carbonyl) group
  • –CHO (carbonyl group at the end of the chain, bonded to H) → Aldehyde group

Note: Both aldehyde and ketone contain the carbonyl group (C=O), but they differ in position — aldehyde is terminal, ketone is internal.

NCERT Ch. 4, Page 78.
E1(c) 3 Marks

What would be observed on adding 5% alkaline potassium permanganate (KMnO₄) solution drop by drop to some warm ethanol taken in a test tube? State the role of KMnO₄ in the reaction and write the chemical equation for the reaction involved.

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Model Answer

On adding alkaline KMnO₄ drop by drop to warm ethanol, the pink colour of KMnO₄ fades/disappears as ethanol gets oxidised to ethanoic acid.

CH₃CH₂OH + [O] --(alkaline KMnO₄)--> CH₃COOH + H₂O

Role of KMnO₄: It acts as an oxidising agent — it provides oxygen [O] needed to convert the alcohol (–OH group) into a carboxylic acid (–COOH group).

NCERT Ch. 4, Page 86. This is the standard oxidation test for ethanol.
E1(d) 3 Marks

Write the name of the compound formed when ethanol is heated at 443 K with excess concentrated H₂SO₄. What is the role of concentrated H₂SO₄ in the reaction? Write the chemical equation for the reaction involved.

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Model Answer

This repeats the reaction from question A2 — a frequently repeated CBSE board question.

CH₃CH₂OH --(Conc. H₂SO₄, 443K, excess)--> CH₂=CH₂ + H₂O

Compound formed: Ethene (C₂H₄)

Role of conc. H₂SO₄: Acts as a dehydrating agent — removes a water molecule from ethanol.

NCERT Ch. 4, Page 85.
E2 5 Marks

Passage: Carbon is a versatile element that forms the basis of all living organisms and many of the things we use. A large variety of compounds is formed because of its tetravalency. Compounds of carbon are formed with oxygen, hydrogen, sulphur, chlorine, and many other elements.

E2(a) 1 Mark

What are hydrocarbons?

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Model Answer

Hydrocarbons are organic compounds made up of only carbon and hydrogen atoms. They are classified as saturated (alkanes) and unsaturated (alkenes and alkynes), and further into open-chain and cyclic (ring) hydrocarbons.

Examples: Methane (CH₄), Ethene (C₂H₄), Ethyne (C₂H₂), Cyclohexane (C₆H₁₂).

NCERT Ch. 4, Page 73.
E2(b) 2 Marks

List two properties of carbon by virtue of which it can form a large number of compounds.

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Model Answer

1. Catenation: Carbon has the unique property of forming bonds with other carbon atoms to form long chains, branched chains, or rings. C–C bonds are very strong and stable.

2. Tetravalency: Carbon has a valency of 4, allowing it to bond with 4 other atoms of carbon, hydrogen, oxygen, nitrogen, sulphur, chlorine, etc., forming a vast variety of compounds.

NCERT Ch. 4, Pages 70–72. One of the most important conceptual answers — asked nearly every year.
E2(c)(i) 3 Marks

Write the formula of the functional group present in (1) aldehydes and (2) ketones. Write the chemical equation for the reaction that occurs between ethanoic acid and ethanol in the presence of a catalyst.

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Model Answer

Functional groups:

  • Aldehyde: –CHO
  • Ketone: >C=O (carbonyl group within the chain)

Reaction between ethanoic acid and ethanol (Esterification):

CH₃COOH + C₂H₅OH --(conc. H₂SO₄ catalyst)--> CH₃COOC₂H₅ + H₂O (Ethyl ethanoate — a sweet-smelling ester)

This reaction is called esterification. The reverse reaction (ester + NaOH → soap + alcohol) is called saponification.

NCERT Ch. 4, Pages 78, 87.
E2(c)(ii) 2 Marks

What are structural isomers? Write the structures of two isomers of butane, C₄H₁₀.

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Model Answer

Structural isomers are compounds that have the same molecular formula but different structural arrangements of atoms, resulting in different physical and sometimes chemical properties.

Two isomers of Butane (C₄H₁₀):

1. n-Butane (straight chain): CH₃–CH₂–CH₂–CH₃ 2. Isobutane / 2-Methylpropane (branched chain): CH₃ | CH₃–CH–CH₃

Both have the formula C₄H₁₀ but different arrangements of carbon atoms — n-butane is unbranched, isobutane is branched.

NCERT Ch. 4, Page 73. Minimum carbon atoms needed for isomerism in alkanes is 4 (butane).
E3 3 Marks

Write the formula and the molecular mass of the third member of the homologous series of alcohols. State how the boiling point of an alcohol changes as one moves from lower to higher members of the homologous series.

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Model Answer

The alcohol homologous series (general formula CₙH₂ₙ₊₁OH) begins as: Methanol (1st), Ethanol (2nd), Propanol (3rd).

Propanol: C₃H₇OH (i.e. CH₃–CH₂–CH₂–OH) Molecular mass = (3×12) + (7×1) + 16 + 1 = 36+7+16+1 = 60 u

Boiling point trend: As we move from lower to higher members of the homologous series of alcohols, the molecular mass increases, which increases the strength of intermolecular forces. Therefore, the boiling point increases as we move up the homologous series.

NCERT Ch. 4, Pages 76–78. Molecular mass calculation combined with trend reasoning is a common 3-mark format.
⚠️ Disclaimer: This page is based on the Class 10 Science (Chemistry) 2024 board exam paper, Chapter 4 – Carbon and Its Compounds. These are theory-based 1, 2, 3, and 5 mark questions exactly as they appear in the board pattern — attempt each one in your own words on paper first, then click "Show Answer" to self-check against the model answer. While every effort has been made to keep the content accurate and aligned with NCERT, there may be typographical errors or minor inaccuracies. Students are strongly advised to verify all answers from the NCERT textbook, their school teacher, or the official CBSE answer key before relying on them for exam preparation. For any doubt, always cross-check with a trusted source.